document.write( "Question 124218: +square root of 49a^4b^8c^12=? \n" ); document.write( "

Algebra.Com's Answer #91024 by bucky(2189) $\"\"$ $\"About$

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You are asked to find the square root of:
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\n" ); document.write( " $\"49a%5E4b%5E8c%5E12\"$
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\n" ); document.write( "Split this into the product of individual terms as follows:
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\n" ); document.write( " $\"%2849%29%2A%28a%5E4%29%2A%28b%5E8%29%2A%28c%5E12%29\"$
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\n" ); document.write( "Now take the square root of the terms in each set of parentheses. For the 49, the square
\n" ); document.write( "root is 7. In the remaining terms the square root of each is found by dividing the exponent
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\n" ); document.write( "So\r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%28a%5E4%29+=+a%5E2\"$
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\n" ); document.write( " $\"sqrt%28b%5E8%29+=+b%5E4\"$
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\n" ); document.write( "and $\"sqrt%28c%5E12%29+=+c%5E6\"$
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\n" ); document.write( "The final answer is just the product of all the individual square roots. Therefore, it is:
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\n" ); document.write( " $\"7%2Aa%5E2%2Ab%5E4%2Ac%5E6\"$
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\n" ); document.write( "Hope this helps you to understand how the problem can be done.
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