document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124106>Question 124106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you solve : Find the equation of the line in slope intercept form that passes through the point (2,5) and is perpendicular to the line 3x-4y =1\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91017 by </B><A HREF=/tutors/aboutme.mpl?userid=RoMaR><B>RoMaR(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RoMaR><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=(3x-1)/4<BR>\n" );
document.write( "so the slope of the first graph is 3/4<BR>\n" );
document.write( "since the line is perpendicular it shoulde be the negative reciprocal of the slope of the first graph<BR>\n" );
document.write( "Using the point-slope form of equation:<BR>\n" );
document.write( "y-5=-4/3(x-2) then evaluating<BR>\n" );
document.write( "y=(-4/3)x+(8/3)+5<BR>\n" );
document.write( "3y=-4x+8+15<BR>\n" );
document.write( "Then the equation if the graph in standard form|<BR>\n" );
document.write( "4x+3y-23=0 </SPAN>\n" );
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