document.write( "Question 124146: Use two variable and the methods for solving word problems to solve:
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document.write( "The sum of two number is 40, one number is 8 more than the other. Find the
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document.write( "numbers \n" );
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Algebra.Com's Answer #91011 by chitra(359)![]() ![]() You can put this solution on YOUR website! Let x and y be 2 numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Givent hat their sum is equal to 40.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 40 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also given that one number(x) is 8 more than the other (y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therfore x = 8 + y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now by back substituion we get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(8 + y) + y = 40 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2y = 40 - 8 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2y = 32 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 16 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now by back substituion we get: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 8 + y \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 8 + 16 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 24 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus the solution.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |