document.write( "Question 124092: what is the solution to y=-2x+4 and y=1x+2 \n" ); document.write( "
Algebra.Com's Answer #91009 by chitra(359)![]() ![]() You can put this solution on YOUR website! The given equation is: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " y = -2x + 4 and \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " y = 1x + 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtracting both the equations we get: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3x + 2 = 0 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3x = - 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now by back substitution in one of the equations we get: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 1(2/3) + 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 2/3 + 2 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Taking LCM, we get: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 8/3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> y = 8/3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus, the solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "regs\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |