document.write( "Question 124082: A train leaves Danville Junction and travels north at a speed of 75km/hr. Two hours later, an express train leaves on a parallel track and travels north at 125km/hr. How far from the station will they meet? \n" ); document.write( "
Algebra.Com's Answer #91000 by PBMathandscience(9)\"\" \"About 
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Distance = speed x time.\r
\n" ); document.write( "\n" ); document.write( "Let T be the time for the express train. Then the time for the first train is T+2.\r
\n" ); document.write( "\n" ); document.write( "The distance covered by the first train is therefore \"75%2A%28T%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "The distance covered by the express train is \"125%2AT\"\r
\n" ); document.write( "\n" ); document.write( "Equating the distances:\r
\n" ); document.write( "\n" ); document.write( "\"75%2A%28T%2B2%29=125%2AT\"\r
\n" ); document.write( "\n" ); document.write( "\"75%2AT%2B150=125%2AT\"\r
\n" ); document.write( "\n" ); document.write( "Subtracting 75*T from both sides:\r
\n" ); document.write( "\n" ); document.write( "\"150=50%2AT\"\r
\n" ); document.write( "\n" ); document.write( "\"3=T\"\r
\n" ); document.write( "\n" ); document.write( "Substitute this value for T into the distance formula for the express train:\r
\n" ); document.write( "\n" ); document.write( "\"D=125%2AT\" \"D=125%2A3\" \"D=375\"\r
\n" ); document.write( "\n" ); document.write( "So they will meet 375 km from the train station. Check by substituting into the equation for the first train.\r
\n" ); document.write( "\n" ); document.write( "\"D=75%2A%28T%2B2%29\" \"375=75%2A%28T%2B2%29\" \"5=T%2B2\" \"3=T\"\r
\n" ); document.write( "\n" ); document.write( "Solution checks.
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