document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124095>Question 124095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular garden is 7 ft. more than twice its width.  If the perimeter of the garden is 56 ft., find the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90994 by </B><A HREF=/tutors/aboutme.mpl?userid=PBMathandscience><B>PBMathandscience(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PBMathandscience><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 2x(Length + Width).  Let W be the width.  Then the length is W+7.  The resultant equation is:\r<BR>\n" );
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document.write( "56=2*((W+7)+W)\r<BR>\n" );
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document.write( "Divide both sides by 2;\r<BR>\n" );
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document.write( "28=W+7+W\r<BR>\n" );
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document.write( "Subtract 7 from both sides:\r<BR>\n" );
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document.write( "21 = 2*W\r<BR>\n" );
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document.write( "Divide by 2\r<BR>\n" );
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document.write( "10.5=W\r<BR>\n" );
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document.write( "Check:  2*((10.5+7)+10.5)=2*(17.5+10.5)=2*(28)=56.\r<BR>\n" );
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document.write( "Solution checks.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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