document.write( "Question 124038: \"f%28x%29=-2x%2B5\" find \"f%28x%2B2%29\" \n" ); document.write( "
Algebra.Com's Answer #90967 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=-2x%2B5\" find \"f%28x%2B2%29\" \r
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\n" ); document.write( "\n" ); document.write( "Just substitute x + 2 everywhere there is an x in f(x)\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%2B2%29=-2%28x%2B2%29%2B5\"
\n" ); document.write( "\"f%28x%2B2%29=-2x-4%2B5\"
\n" ); document.write( "\"f%28x%2B2%29=-2x%2B1\"
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