document.write( "Question 123996: Ok, so I have my Honors Algebra 2 FINAL tomorrow and there is this certain type of problem I just don't understand. No matter how many times I try these types of problems I just can't seem to get them right. Could someone maybe explain to me how to do the following type of problem? That would be a huge help. I'm hoping that maybe a second explanation other than the one from my teacher will help me finally understand.\r
\n" ); document.write( "\n" ); document.write( "You could use this problem as an example. \r
\n" ); document.write( "\n" ); document.write( "Directions: Solve each equation for \"0%3C=+%28theta%29%3C+2%28pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-5cos%28theta%29+=+cos%28theta%29+-+3%28square+root%293\"
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Algebra.Com's Answer #90959 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Try this:
\n" ); document.write( "\"-5cos%28theta%29+=+cos%28theta%29-3sqrt%283%29\" (I hope I got this right): Subtract \"cos%28theta%29\"from both sides.
\n" ); document.write( "\"-6cos%28theta%29+=+-3sqrt%283%29\" Now divide both sides by -6.
\n" ); document.write( "\"cos%28theta%29+=+sqrt%283%29%2F2\"
\n" ); document.write( "Now you are looking for the angle theta whose cosine is \"sqrt%283%29%2F2\" or:
\n" ); document.write( "\"theta+=+cos%5E%28-1%29%28sqrt%283%29%2F2%29\" or
\n" ); document.write( "\"theta+=+arccos%28sqrt%283%29%2F2%29\"
\n" ); document.write( "\"theta+=+30\"degrees.
\n" ); document.write( "In radians: \"theta+=+%28pi%29%2F6\"Radians.
\n" ); document.write( "Check:(Degrees)
\n" ); document.write( "\"-5cos%28theta%29+=+cos%28theta%29-3sqrt%283%29\" Substitute \"theta+=+30\"
\n" ); document.write( "\"-5cos%2830%29+=+cos%2830%29-3sqrt%283%29\"
\n" ); document.write( "\"-5%280.866%29+=+%280.866%29-3%281.732%29\"
\n" ); document.write( "\"-4.33+=+-4.33\"
\n" ); document.write( "Check: (Radians)
\n" ); document.write( "\"-5cos%28theta%29+-+cos%28theta%29-3sqrt%283%29\" Substitute\"theta+=+%28pi%29%2F6\"
\n" ); document.write( "\"-5cos%28%28pi%29%2F6%29+=+cos%28%28pi%29%2F6%29-3sqrt%283%29\"
\n" ); document.write( "\"-5%280.866%29+=+%280.866%29-3%281.732%29\"
\n" ); document.write( "\"-4.33+=+-4.33\"
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