document.write( "Question 123932: EMILY HAS 15 MORE DIMES THAN QUARTERS. IF THE TOTAL VALUE OF THE COINS IS $3.95, HOW MANY DIMES AND QUARTERS DOES SHE HAVE? \n" ); document.write( "
Algebra.Com's Answer #90951 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! D=Q+15 \n" ); document.write( ".25Q+.10D=3.95 \n" ); document.write( "REPLACING D WITH(Q+15) THEN: \n" ); document.write( ".25Q+.10(Q+15)=3.95 \n" ); document.write( ".25Q+.10Q+1.5=3.95 \n" ); document.write( ".35Q=3.95-1.5 \n" ); document.write( ".35Q=2.45 \n" ); document.write( "Q=2.45/.35 \n" ); document.write( "Q=7 NUMBER OF QUARTERS. \n" ); document.write( "D=7+15=22 NUMBER OF DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".25*7+.10*22=3.95 \n" ); document.write( "1.75+2.2=3.95 \n" ); document.write( "3.95=3.95\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |