document.write( "Question 123989: A boat travels 45 mi upstream (against the current) in 5h. the boat travels the same distance downstream 3 h. what is the rate of the boat in still water? what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #90925 by checkley71(8403)\"\" \"About 
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D=RT
\n" ); document.write( "45=5R
\n" ); document.write( "R=45/5
\n" ); document.write( "R=9 MPH AGAINST THE CURRENT.
\n" ); document.write( "45=3R
\n" ); document.write( "R=45/3
\n" ); document.write( "R=15 MPH WITH THE CURRENT.
\n" ); document.write( "(15-9)/2=6/2=3 MPH IS THE RATE OF THE CURRENT.\r
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