document.write( "Question 123989: A boat travels 45 mi upstream (against the current) in 5h. the boat travels the same distance downstream 3 h. what is the rate of the boat in still water? what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #90925 by checkley71(8403) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "45=5R \n" ); document.write( "R=45/5 \n" ); document.write( "R=9 MPH AGAINST THE CURRENT. \n" ); document.write( "45=3R \n" ); document.write( "R=45/3 \n" ); document.write( "R=15 MPH WITH THE CURRENT. \n" ); document.write( "(15-9)/2=6/2=3 MPH IS THE RATE OF THE CURRENT.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |