document.write( "Question 123895: Edwin is 6 years older than his brother Alvin. In two years, Edwin will be 20 more than one-third of Alvin's age. How old are the brothers now? \n" ); document.write( "
Algebra.Com's Answer #90890 by bucky(2189)\"\" \"About 
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Let E represent Edwin's present age and A represent Alvin's present age.
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\n" ); document.write( "The problem tells you first that presently Edwin is 6 years older than his brother Alvin. That
\n" ); document.write( "means that if you take 6 years off Edwin's present age, the answer you get is equal to
\n" ); document.write( "Alvin's present age. In equation form this is:
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\n" ); document.write( "E - 6 = A
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\n" ); document.write( "Next the problem indicates what the relationship between their ages will be 2 years from now.
\n" ); document.write( "In two years from now Edwin's age will be his present age plus 2 ... or E + 2. And also in 2 years
\n" ); document.write( "from now Alvin's age will be his present age plus 2 ... or A + 2.
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\n" ); document.write( "The problem then tells you that 2 years from now Edwin's age at that time will be 20 more than
\n" ); document.write( "a third of Alvin's age. This tells you that if you take 20 years away from Edwin's
\n" ); document.write( "age at that time the answer will equal a third of Alvin's age at that time.
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\n" ); document.write( "Well, 20 years off Edwin's age in 2 years will be (E + 2) - 20 and this simplifies
\n" ); document.write( "to E - 18.
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\n" ); document.write( "And a third of Alvin's age in 2 years will be \"%281%2F3%29%2A%28A%2B2%29\"
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\n" ); document.write( "Since we know these two are to be equal, we can set them equal in the equation form of:
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\n" ); document.write( "\"E-18+=+%281%2F3%29%2A%28A+%2B+2%29\"
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\n" ); document.write( "We can get rid of the denominator 3 by multiplying both sides of this equation by 3 to
\n" ); document.write( "convert the equation to:
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\n" ); document.write( "\"3E+-+54+=+A+%2B+2\"
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\n" ); document.write( "But way back at the start our first equation said that E - 6 = A. So wherever we see A we can
\n" ); document.write( "substitute it equal E - 6. Substituting E-6 for A in the equation above results in the equation becoming:
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\n" ); document.write( "\"3E+-+54+=+E+-+6+%2B2\"
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\n" ); document.write( "Combine the constants -6 and +2 on the right side to get -4 which reduces the equation to:
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\n" ); document.write( "\"3E+-+54+=+E+-+4\"
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\n" ); document.write( "Get rid of the -54 on the left side by adding +54 to both sides and the equation becomes:
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\n" ); document.write( "\"3E+=+E+%2B+50\"
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\n" ); document.write( "Get rid of the E on the right side by subtracting E from both sides to get:
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\n" ); document.write( "\"2E+=+50\"
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\n" ); document.write( "Solve for E by dividing both sides by 2 and you have:
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\n" ); document.write( "\"E+=+25\"
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\n" ); document.write( "So Edwin's present age is 25. And since Edwin is 6 years older than Alvin, then Alvin's present
\n" ); document.write( "age is 25 - 6 = 19 years old.
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\n" ); document.write( "In two years from the present, Edwin will be 27 and Alvin will be 21. (Still 6 years difference
\n" ); document.write( "in their ages, just as there will always be.)
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\n" ); document.write( "If you took 20 from Edwin's age of 27 you get an answer of 7. And if you took a third of
\n" ); document.write( "Alvin's age of 21 you also get an answer of 7. So our answer satisfies both of the sets of
\n" ); document.write( "conditions given in the problem.
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\n" ); document.write( "In summary, the answer to this problem is that Edwin is currently 25 years old and Alvin is
\n" ); document.write( "currently 19 years old.
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\n" ); document.write( "Hope all this helps you to understand the problem and how to work it.
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