document.write( "Question 123895: Edwin is 6 years older than his brother Alvin. In two years, Edwin will be 20 more than one-third of Alvin's age. How old are the brothers now? \n" ); document.write( "
Algebra.Com's Answer #90889 by applesrbest(7)![]() ![]() ![]() You can put this solution on YOUR website! Let Alvin's age now be x, and Edwin's age be x+6.\r \n" ); document.write( "\n" ); document.write( "Therefore, in 2 years' time, \r \n" ); document.write( "\n" ); document.write( " x+8 = (1/3)(x+2) + 20 \n" ); document.write( " x+8 = (1/3)(x) + 62/3 \n" ); document.write( "(2/3)x = 38/3 \n" ); document.write( " x = 19\r \n" ); document.write( "\n" ); document.write( "Hence, Alvin is 19 years old, and Edwin is x+6 = 19+6 = 25 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |