document.write( "Question 123893: Please help me solve this equation. \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #90888 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Equations in this form [fractions on both sides] are called proportions. You can convert a proportion \n" ); document.write( "to a more conventional equation form by multiplying the numerator on one side by the denominator \n" ); document.write( "on the other side. If you to that for both numerators, you get two products and you separate the \n" ); document.write( "two products by an equal sign. Then just solve the resulting equation using algebraic \n" ); document.write( "procedures. Let's apply this method to your problem. \n" ); document.write( ". \n" ); document.write( "Begin by multiplying the numerator \n" ); document.write( "resulting distributed multiplication results in the product \n" ); document.write( ". \n" ); document.write( "Next multiply the numerator \n" ); document.write( "resulting product is \n" ); document.write( ". \n" ); document.write( "Separate these two products with an equal sign and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get this in conventional quadratic form by subtracting \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Factor the left side of this equation to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice that this equation will be true if either of the factors on the left side equal zero \n" ); document.write( "because multiplying by a zero on the left side will make the entire left side equal to \n" ); document.write( "zero and therefore equal to the right side. To find the values of t that will make a factor \n" ); document.write( "equal to zero, just set the two factors equal to zero (one factor at a time) and solve for t. \n" ); document.write( ". \n" ); document.write( "First: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Add 6 to both sides and this becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 2 from both sides and this becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So the two answers to this problem are \n" ); document.write( ". \n" ); document.write( "You can check these answers by substituting them one at a time into the original equation you \n" ); document.write( "were given and then working out the answers to make sure the left side of the equation does \n" ); document.write( "in fact equal the right side. For example, let's check to see if the given equation is \n" ); document.write( "equal on both sides when t is equal to +6. The original equation is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Replace t with +6 and this equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The denominator on the right side multiplies out to give 12 + 6 = 18 and this makes the \n" ); document.write( "equation reduce to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice that both sides reduce to \n" ); document.write( ". \n" ); document.write( "If you try the same check by substituting -2 for t you will find that is also works out such \n" ); document.write( "that both sides are equal. So both answers check. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem and how you can start to work out proportions by \n" ); document.write( "using cross multiplication to get them into a more conventional form. \n" ); document.write( ". \n" ); document.write( " |