document.write( "Question 123857: how do you express f(x)=-3(x-2)^2+5 in standard form? What formula do you use? \n" ); document.write( "
Algebra.Com's Answer #90860 by johnnico6426(16)\"\" \"About 
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To put a quadratic equation in standard form, it must follow the format:
\n" ); document.write( "\"y=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "To put the given into standard form, we must distribute 3 with \"%28x-2%29%28x-2%29\". (\"%28x-2%29%28x-2%29\"=\"%28x-2%29%5E2\".) If you do it, you should come up with \"-3x%5E2%2B12x-12\". The only thing left to do is to add 5 to 12 in order to simplify it. In conclusion, the equation \"f%28x%29=-3%28x-2%29%5E2%2B5\" in standard form is \"y=3x%5E2%2B12x-17\".
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