document.write( "Question 123842: What formula do you use to put this in vertex form where you can graph it? What are the \"zeros\" of this equation? and how do you find the \"zeros\".\r
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\n" ); document.write( "\n" ); document.write( "f(x)=-3(x-2)^2+5
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Algebra.Com's Answer #90849 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
A zero means to let f(x) = 0 and solve for x:\r
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\n" ); document.write( "\n" ); document.write( "f(x)=-3(x-2)^2 + 5 =0\r
\n" ); document.write( "\n" ); document.write( "Subtract 5 from each side:\r
\n" ); document.write( "\n" ); document.write( "\"-3%28x-2%29%5E2++=-+5\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by -3:\r
\n" ); document.write( "\n" ); document.write( "\"+%28x-2%29%5E2=5%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Take the squsre root of each side:
\n" ); document.write( "\"x-2=0%2B-sqrt%285%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add 2 to each side:
\n" ); document.write( "\"x=2%2B-sqrt%285%2F3%29+\"\r
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\n" ); document.write( "\n" ); document.write( "There are other ways to write this, by rationalizing the denominator:
\n" ); document.write( "\"x=2%2B-+sqrt%28%285%2F3%29%2A%283%2F3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2B-+sqrt%2815%2F9%29\"
\n" ); document.write( "\"x=2%2B-+%28sqrt%2815%29%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "You may need to express this with a common denominator:
\n" ); document.write( "\"+x=%286%2B-sqrt%2815%29%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "R^2
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