document.write( "Question 123785: The length of a rectangle is 5 meters longer than the width.Find the length and width if the perimeter is 54 meters. \n" ); document.write( "

Algebra.Com's Answer #90846 by nadinadan(32) $\"\"$ $\"About$

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So let's say that the length is L and the width is W, of the rectangle.
\n" ); document.write( "The problem says that L=5+W, the length is 5 more than width.
\n" ); document.write( "We know that the perimeter of the rectangle is 2L+2W,and the problem says that the perimeter is 54, so 2L+2W=54.
\n" ); document.write( "We have 2 equations now,
\n" ); document.write( "L=5+W and
\n" ); document.write( "2L+2W=54 if we replace the first equation into the second one we have
\n" ); document.write( "2(5+W)+2W=54, that makes 10+2W+2W=54 If we simplify, 4W=54-10 so 4W=44 amd W=44/4 which makes W=11.
\n" ); document.write( "Now we replace W in the first equation L=5+W, so L=5+11 so L=16
\n" ); document.write( "To verify ourselves, we replace L and W in the perimeter equation.
\n" ); document.write( "2L+2W=54 2*16+2*11=54 32+22=54, so we did good.
\n" ); document.write( "Let me know if you need more help.
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