document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123635>Question 123635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average speed of one airplane is 200 mph faster than that of an automobile.  If the automobile starts at 3 am and the airplane starts from the same place at 11 am, they will have traveled the same number of miles by 1 pm.  Find the rate of the automobile.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90842 by </B><A HREF=/tutors/aboutme.mpl?userid=PBMathandscience><B>PBMathandscience(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PBMathandscience><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the car be \"X\".  From 3 am until 1 pm (10 hours), the car will travel 10*X miles.  \r<BR>\n" );
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document.write( "The speed of the airplane is (X +200).  From 11 am until 1 pm (2 hours), the plane will travel 2*(X+200).\r<BR>\n" );
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document.write( "The distance travelled is the same, so:\r<BR>\n" );
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document.write( "10*X = 2*(x+200)= 2x+400\r<BR>\n" );
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document.write( "Subtract 2*X from both sides:\r<BR>\n" );
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document.write( "8*X = 400<BR>\n" );
document.write( "X = 400/8 = 50 mph.\r<BR>\n" );
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