document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123814>Question 123814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"A\" IS DRIVING 40 MPH. AFTER \"A\" AS DRIVEN 30 MILES, \"B\" STARTS DRIVING IN THE SAME DIRECTION AT WHAT RATE MUST \"B\" DRIVE TO CATCH UP TO \"A\" IN 5 HOURS?   \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90839 by </B><A HREF=/tutors/aboutme.mpl?userid=PBMathandscience><B>PBMathandscience(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PBMathandscience><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In five hours, A will have driven 40mph * 5hours = 200 miles, plus the additional 30 mile head start, so A will have travelled a total of 230 miles.  B must cover this same distance in 5 hours, so B's speed must be 230 miles/5 hours or 46 mph. </SPAN>\n" );
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