document.write( "Question 123805: art leaves at 10am traveling at 50mph. AT 11:30am Jennifer starts in the same direction at 45mph. when will they be 100 miles apart? \n" ); document.write( "
Algebra.Com's Answer #90818 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 50X=45(X-1.5)+100 \n" ); document.write( "50X=45X-67.5+100 \n" ); document.write( "50X-45X=32.5 \n" ); document.write( "5X=32.5 \n" ); document.write( "X=32.5/5 \n" ); document.write( "X=6.5 HOURS THEY WILL BE 100 MILES APART. \n" ); document.write( "50*6.5=45*5+100 \n" ); document.write( "325=225+100 \n" ); document.write( "325=325 \n" ); document.write( " |