document.write( "Question 123791: The length of a rectangle is 5 meters longer than the width. Find the length and width if the perimeter is 54 meters. \n" ); document.write( "
Algebra.Com's Answer #90810 by nadinadan(32)![]() ![]() ![]() You can put this solution on YOUR website! Let's change the words problem in math operations. \n" ); document.write( "The problem says: \n" ); document.write( "L=5+W where L is the Length and W is the width. \n" ); document.write( "And 2L+2W=54 The perimeter of the rectangle is L+L+W+W=2L+2W \n" ); document.write( "So we have 2 equations: \n" ); document.write( "L=5+W \n" ); document.write( "2L+2W=54 we replace the first ecuation into the second one, so insted of L we will have (5+L) \n" ); document.write( "So the second ecuation changes to \n" ); document.write( "2(5+W)+2W=54 so 10+2W+2W=54 so 4W=54-10 so 4W=44 so W=11 \n" ); document.write( "than in L=5+W, we replace W=11, so L=5+11=16.\r \n" ); document.write( "\n" ); document.write( "So L=16 and W=11. \n" ); document.write( " \n" ); document.write( " |