document.write( "Question 123791: The length of a rectangle is 5 meters longer than the width. Find the length and width if the perimeter is 54 meters. \n" ); document.write( "
Algebra.Com's Answer #90810 by nadinadan(32)\"\" \"About 
You can put this solution on YOUR website!
Let's change the words problem in math operations.
\n" ); document.write( "The problem says:
\n" ); document.write( "L=5+W where L is the Length and W is the width.
\n" ); document.write( "And 2L+2W=54 The perimeter of the rectangle is L+L+W+W=2L+2W
\n" ); document.write( "So we have 2 equations:
\n" ); document.write( "L=5+W
\n" ); document.write( "2L+2W=54 we replace the first ecuation into the second one, so insted of L we will have (5+L)
\n" ); document.write( "So the second ecuation changes to
\n" ); document.write( "2(5+W)+2W=54 so 10+2W+2W=54 so 4W=54-10 so 4W=44 so W=11
\n" ); document.write( "than in L=5+W, we replace W=11, so L=5+11=16.\r
\n" ); document.write( "\n" ); document.write( "So L=16 and W=11.
\n" ); document.write( "
\n" ); document.write( "
\n" );