document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123752>Question 123752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure copper was mixed with a 23% copper alloy to produce an alloy that was 32% copper. how much of each were used to produce 44kg of 32% alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90776 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (44-X)+.23X=.32*44<BR>\n" );
document.write( "44-X+.23X=14.08<BR>\n" );
document.write( "-77X=14.08-44<BR>\n" );
document.write( "-.77X=-29.92<BR>\n" );
document.write( "X=-29.92/-.77<BR>\n" );
document.write( "X=38.86 <BR>\n" );
document.write( "44-38.86=5.14 OZ OF PURE COPPER IS USED.<BR>\n" );
document.write( "(44-38.86)+.23*38.86=14.08<BR>\n" );
document.write( "5.14+8.94=14.08<BR>\n" );
document.write( "14.08=14.08<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );