document.write( "Question 123685: Find three consecutive even integers such that the sum of the twice the first, six times the second and three times the third is 133. \n" ); document.write( "
Algebra.Com's Answer #90738 by checkley71(8403)\"\" \"About 
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x, x+2, x+4
\n" ); document.write( "2x+6(x+2)+3(x+4)=133
\n" ); document.write( "2x+6x+12+3x+12=133
\n" ); document.write( "11x=133-24
\n" ); document.write( "11x=109
\n" ); document.write( "x=109/11
\n" ); document.write( "x=9.9090909 not an even number.
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\n" ); document.write( "ARE YOU SURE YOU HAVE THE PROPER WORDING IN THIS PROBLEM??????
\n" ); document.write( "THREE EVEN NUMBERS WHEN ADDED ADD OR MULTIPLIED MUST BE AN EVEN NUMBER 133 IS NOT AN EVEN NUMBER.
\n" ); document.write( "IF THESE ARE NOT EVEN NINTERGERS THEN:
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\n" ); document.write( "x, x+1, x+2 are the integers.
\n" ); document.write( "2x+6(x+1)+3(x+2)=133
\n" ); document.write( "2x+6x+6+3x+6=133
\n" ); document.write( "11x=133-12
\n" ); document.write( "11x=121
\n" ); document.write( "x=121
\n" ); document.write( "11x=11 answer for the first integer.
\n" ); document.write( "11=1=12
\n" ); document.write( "11+2=13
\n" ); document.write( "proof:
\n" ); document.write( "2*11+6*12+3*13=133
\n" ); document.write( "22+72+39=133
\n" ); document.write( "133=133\r
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