document.write( "Question 123457This question is from textbook College Prepatory Mathematics 1
\n" ); document.write( ": I cannot figure out the Pythagorean theorem when there is two variables and one regular number. I need to solve $\"x%5E2%2B3x%5E2=18%5E2\"$ .I have(well I think) already between 5 2/3 and 5.7. \n" ); document.write( "

Algebra.Com's Answer #90720 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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solve $\"x%5E2%2B3x%5E2=18%5E2\"$
\n" ); document.write( ":
\n" ); document.write( "x^2 and 3x^2 are like terms, just add them together, square 18 to get 324
\n" ); document.write( " $\"4x%5E2+=+324\"$
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( " $\"x%5E2+=+324%2F4\"$
\n" ); document.write( " $\"x%5E2+=+81\"$
\n" ); document.write( "x = $\"sqrt%2881%29\"$
\n" ); document.write( "x = 9
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution:
\n" ); document.write( "9^2 + 3(9^2) =
\n" ); document.write( "81 + 3(81) =
\n" ); document.write( "81 + 343 = 324, which is 18^2
\n" ); document.write( " \n" ); document.write( "

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