document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123670>Question 123670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with this problem...it's a handful. Any help is appreciated. Thanks.\r<BR>\n" );
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document.write( "Question:\r<BR>\n" );
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document.write( "Solve for y\r<BR>\n" );
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document.write( "3(y+7)/7y   -   (4y-7)/6  =  (7y+10)/3y  -  2(7y-1)/21 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90714 by </B><A HREF=/tutors/aboutme.mpl?userid=nadinadan><B>nadinadan(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nadinadan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So, let's find the common denominator for all fractions. 42y is the one so we multiply the first fraction by 6, the second fractions by 7y, the third by 14 and the fourth by 2y.<BR>\n" );
document.write( "18(y+7) -7y(4y-7)- 14(7y+10)+4y(7y-1) / 42y Simplify<BR>\n" );
document.write( "(18y+126-28y^2+49y-98y-140+28y^2-4y)/ 42y Simplify more<BR>\n" );
document.write( "(70y-14)/42y   -> (10y-2)/6y is the answer\r<BR>\n" );
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