document.write( "Question 123665: Please just don't get it....Suppose that the function?
\n" ); document.write( "Suppose that the function P=13+45ln x represents the percentage of inbound e-mail in the U.S. that is consideed spam, where x is the number of years after 2000. \r
\n" ); document.write( "\n" ); document.write( "Carry all calculations to six decimals on each intermediate step, when necessary. \r
\n" ); document.write( "\n" ); document.write( "a) Use this model to approximate the percentage of spam in the year 2003. \r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "b) Use this model to approximate the year that the percent of spam will reach 95% provided that law enforcement regarding spammers does not change? \r
\n" ); document.write( "\n" ); document.write( "Answer:
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Algebra.Com's Answer #90713 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Suppose that the function P=13+45ln x represents the percentage of inbound e-mail in the U.S. that is consideed spam, where x is the number of years after 2000.
\n" ); document.write( "Carry all calculations to six decimals on each intermediate step, when necessary.
\n" ); document.write( "a) Use this model to approximate the percentage of spam in the year 2003.
\n" ); document.write( "Answer: P(2003-2000) = 13+45ln(3) = 62.4376%
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\n" ); document.write( "b) Use this model to approximate the year that the percent of spam will reach 95% provided that law enforcement regarding spammers does not change?
\n" ); document.write( "95 = 13 + 45ln(x)
\n" ); document.write( "82 = 45ln(x)
\n" ); document.write( "ln(x) = 1.8222
\n" ); document.write( "x = e^1.8222 = 6.1856
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\n" ); document.write( "95% spam will be reached in 2000+6.1856 or in the year 2007
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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