document.write( "Question 18865: I need help, please!
\n" ); document.write( "Simplify
\n" ); document.write( " $\"%28x%5E-2-y%5E-2%29%2F%28x%5E-1-y%5E-1%29\"$ \n" ); document.write( "

Algebra.Com's Answer #9071 by xcentaur(357) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28x%5E-2-y%5E-2%29%2F%28x%5E-1-y%5E-1%29\"$
\n" ); document.write( "A negative power means that you can put the reciprocal of that number
\n" ); document.write( "ie. x^-2 is the same as (1/x^2)
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\n" ); document.write( "keeping that in mind,this expression becomes
\n" ); document.write( " $\"%28%281%2Fx%5E2%29-%281%2Fy%5E2%29%29%2F%28%281%2Fx%29-%281%2Fy%29%29\"$
\n" ); document.write( "Taking LCM this becomes,
\n" ); document.write( " $\"%28%28y%5E2-x%5E2%29%2F%28x%5E2%2Ay%5E2%29%29%2F%28%28y-x%29%2F%28xy%29%29\"$
\n" ); document.write( "Now we get,
\n" ); document.write( " $\"%28%28y%5E2-x%5E2%29%2F%28x%5E2%2Ay%5E2%29%29%2A%28%28xy%29%2F%28y-x%29%29\"$
\n" ); document.write( "**(y^2-x^2)=(y-x)(y+x).Substituting this we get,
\n" ); document.write( " $\"+%28%28y-x%29%28y%2Bx%29%2F%28x%5E2%2Ay%5E2%29%29%2A%28%28xy%29%2F%28y-x%29%29+\"$
\n" ); document.write( "**(x^2*y^2)=(xy)(xy).Substituting this we get,
\n" ); document.write( " $\"+%28%28y-x%29%28y%2Bx%29%2F%28xy%2Axy%29%29%2A%28%28xy%29%2F%28y-x%29%29+\"$
\n" ); document.write( "Now cancelling out terms we get,
\n" ); document.write( " $\"+%28%28y%2Bx%29%2F%28xy%29%29+\"$
\n" ); document.write( "And this is the final answer.
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\n" ); document.write( "Hope this helps,
\n" ); document.write( "Prabhat \n" ); document.write( "

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