document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123618>Question 123618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain radioactive element decays to 1/2 of its original amount every 20 years. If there was 100mg to start with, how much will be present after 200 years? Set up an equation and solve the problem. Can someone please help me ?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90680 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain radioactive element decays to 1/2 of its original amount every 20 years. If there was 100mg to start with, how much will be present after 200 years? Set up an equation and solve the problem.<BR>\n" );
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document.write( "A(t)=A(0)*(1/2)^(t/20)<BR>\n" );
document.write( "A(t) is the amount you have at a certain time.<BR>\n" );
document.write( "A(0) is the amount you have when you start.<BR>\n" );
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document.write( "A(200)=100*(1/2)^(200/20)<BR>\n" );
document.write( "A(200) = 100*0.0313<BR>\n" );
document.write( "A(200) = 31.3 mg<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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