document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123620>Question 123620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am suppose to draw the graph of each line using its y-intercept and its slope..I have gone over the chapter and am just confused on how exactly i find that using this equation. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%2B3y=9 ALIGN=MIDDLE  ALT=\"4x%2B3y=9\"   DISABLED_style= \"max-width:90%; height:auto;\" > I am so ready to tear my hair out...can someone help?\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90671 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE STANDARD LINE FORMULA IS:<BR>\n" );
document.write( "Y=mX+b WHERE m=THE SLOPE & b=Y INTERCEPT.<BR>\n" );
document.write( "NOW CONVERT YOUR EQUATION TO THIS FORM THUS:<BR>\n" );
document.write( "4X+3Y=9<BR>\n" );
document.write( "3Y=-4X+9<BR>\n" );
document.write( "Y=-4X/3+9/3<BR>\n" );
document.write( "Y=-4X/3+3 ANSWER<BR>\n" );
document.write( "THIS REPRESENTS A LINE WITH A SLOPE OF -4/3 & THE Y INTERCEPT IS 3.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+y+=+-4x%2F3+%2B3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+y+=+-4x%2F3+%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x300 pixels, x from -5 to 5, y from -5 to 5, y = -4x/3 +3). <BR>\n" );
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