document.write( "Question 18836: Extract SquareRoots\r
\n" ); document.write( "\n" ); document.write( "(3x-8)^2=16\r
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\n" ); document.write( "\n" ); document.write( "6x^2=150 \n" ); document.write( "

Algebra.Com's Answer #9067 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
1) $\"%283x-8%29%5E2+=+16\"$ Take (extract) the square root of both sides.
\n" ); document.write( " $\"sqrt%28%283x-8%29%5E2%29+=+sqrt%2816%29\"$
\n" ); document.write( " $\"%283x-8%29+=+4\"$ Add 8 to both sides. Note: When you take the square root, you really get two answers...one is + and the other is -, so:
\n" ); document.write( " $\"3x-8+=+4\"$ or $\"3x-8+=+-4\"$
\n" ); document.write( " $\"3x+=+12\"$ Divide both sides by 3.
\n" ); document.write( " $\"x+=+4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x-8+=+-4\"$ Add 8 to both sides.
\n" ); document.write( " $\"3x+=+4\"$ Divide both sides by 3.
\n" ); document.write( " $\"x+=+4%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( "2)
\n" ); document.write( " $\"6x%5E2+=+150\"$ First, divide both sides by 6.
\n" ); document.write( " $\"x%5E2+=+25\"$ Now take the square root of both sides.
\n" ); document.write( " $\"sqrt%28x%5E2%29+=+sqrt%2825%29\"$
\n" ); document.write( " $\"x+=+5\"$ or $\"x+=+-5\"$
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