document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123597>Question 123597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Are the following lines parallel, perpendicular, or neither? \r<BR>\n" );
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document.write( "x-6y=12 <BR>\n" );
document.write( "6x+y=6  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90664 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-6y=12 <BR>\n" );
document.write( "6x+y=6\r<BR>\n" );
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document.write( " first we can find y in each equation then\r<BR>\n" );
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document.write( "y = (x-12)/6 = (1/6)x-2<BR>\n" );
document.write( "y = -6x+6    so coeficients of x are 1/6 and -6 then (1/6)(-6)=-1 then   \r<BR>\n" );
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document.write( "the lines are perpendicular.\r<BR>\n" );
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document.write( "(lines ax+b  and cx+d are perpendicular if only if ac=-1) </SPAN>\n" );
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