document.write( "Question 123564: A tub contains 300 l of a 32% salt solution. How much water must be added to reduce it to a 20% solution? \n" ); document.write( "

Algebra.Com's Answer #90646 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"w\"$ = amount of water to be added
\n" ); document.write( "In words:
\n" ); document.write( "salt / (original solution + added water) = 20%
\n" ); document.write( " $\".32%2A300+=+96\"$ l of salt
\n" ); document.write( " $\"96+%2F+%28300+%2B+w%29+=+.2\"$
\n" ); document.write( " $\"96+=+.2%28300+%2B+w%29\"$
\n" ); document.write( " $\"96+=+60+%2B+.2w\"$
\n" ); document.write( " $\".2w+=+36\"$
\n" ); document.write( " $\"w+=+180\"$ l of water need to be added
\n" ); document.write( "check:
\n" ); document.write( " $\"96+%2F+%28300+%2B+w%29+=+.2\"$
\n" ); document.write( " $\"96+%2F+%28300+%2B+180%29+=+.2\"$
\n" ); document.write( " $\"96+%2F+480+=+.2\"$
\n" ); document.write( " $\".2+=+.2\"$
\n" ); document.write( "OK \n" ); document.write( "

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