document.write( "Question 123513: Find 3 consecutive multiples of six such that 4 times the first exceeds twice the third by 12. \n" ); document.write( "
Algebra.Com's Answer #90619 by ankor@dixie-net.com(22740)\"\" \"About 
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Find 3 consecutive multiples of six such that 4 times the first exceeds twice the third by 12.
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\n" ); document.write( "Let x = 1st multiply of 6
\n" ); document.write( "Then
\n" ); document.write( "(x+6) = 2nd multiply of 6
\n" ); document.write( "and
\n" ); document.write( "(x+12) = 3rd multiply of 6
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\n" ); document.write( "Write an equation from the statement,
\n" ); document.write( "\"4 times the first exceeds twice the third by 12.\"
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\n" ); document.write( "4x = 2(x+12) + 12
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\n" ); document.write( "4x = 2x + 24 + 12
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\n" ); document.write( "4x - 2x = 36
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\n" ); document.write( "2x = 36
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\n" ); document.write( "x = 18
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\n" ); document.write( "The three multiples of 6 are: 18, 24, 30
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"4 times the first exceeds twice the third by 12.\"
\n" ); document.write( "4(18) = 2(30) + 12
\n" ); document.write( " 72 = 60 + 12 \n" ); document.write( "
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