document.write( "Question 123406: A grocer buys walnuts for $0.45/lb. and pecans for $0.60/lb. If the nuts must be combined for a 90 lb. mix worth $0.55/lb, how many pounds of walnuts must be added? \n" ); document.write( "
Algebra.Com's Answer #90615 by ankor@dixie-net.com(22740)\"\" \"About 
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grocer buys walnuts for $0.45/lb. and pecans for $0.60/lb. If the nuts must be combined for a 90 lb. mix worth $0.55/lb, how many pounds of walnuts must be added?
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\n" ); document.write( "Let x = no. of lbs of walnuts required
\n" ); document.write( "then
\n" ); document.write( "(90-x) = no. of lbs of pecans required
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\n" ); document.write( "we can do this without the decimals, just use cents:
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\n" ); document.write( "45x + 60(90-x) = 55(90)
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\n" ); document.write( "45x = 5400 - 60x = 4950
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\n" ); document.write( "45x - 60x = 4950 - 5400
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\n" ); document.write( "-15x = -450
\n" ); document.write( "x = \"%28-450%29%2F%28-15%29\"
\n" ); document.write( "x = +30 lb of walnuts
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\n" ); document.write( "that would leave 60 lb of pecans; see if that checks out
\n" ); document.write( "45(30) + 60(60) = 55(90)
\n" ); document.write( "1350 + 3600 = 4950; confirms our solution \n" ); document.write( "
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