document.write( "Question 123418: A factory employs skilled labores at 25 an hour and un skilled at 12 an hour. The hourly cost of the factorys 24 workers is $405. Howmany of each type of laborer works at the factory? \n" ); document.write( "
Algebra.Com's Answer #90588 by johnnico6426(16)\"\" \"About 
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Since there are 24 total workers, we can conclude that \"x%2By=24\" (x represents the number of skilled workers and y represents the number of unskilled workers). In addition, since the total cost of paying off the workers is $405.00, we can also conclude that \"25x%2B12y=405\". (We put 25 next to x because we are paying the skilled workers $25.00. We put 12 next to y because we are paying the unskilled workers with $12.00.) Now that we have two system of equations, we can use any method to solved it. For the sake of easines, I will solve the equation using substitution.\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=24\"
\n" ); document.write( "\"25x%2B12y=405\"
\n" ); document.write( "Solve for y in the first equation.
\n" ); document.write( "\"y=24-x\"
\n" ); document.write( "Plug they in the second equation.
\n" ); document.write( "\"25x%2B12%2824-x%29=405\"
\n" ); document.write( "Solve for x.
\n" ); document.write( "\"x=9\"
\n" ); document.write( "Plug x in the first equation.
\n" ); document.write( "\"%289%29%2By=24\"
\n" ); document.write( "Solve for y.
\n" ); document.write( "\"y=15\"
\n" ); document.write( "Solutions:
\n" ); document.write( "\"x=9\"and\"y=15\"\r
\n" ); document.write( "\n" ); document.write( "In conclusion, there are 9 skilled and 15 unskilled workers.
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