document.write( "Question 123407: An alloy of tin is 16% tin. How much tin must be added to make 820 lbs of alloy that is 18% tin? Answer to the nearest tenth. \n" ); document.write( "
Algebra.Com's Answer #90583 by checkley71(8403)\"\" \"About 
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.16X+(820-X)=.18*820
\n" ); document.write( ".16X+820-X=147.6
\n" ); document.write( "-.84X=147.6-820
\n" ); document.write( "-.84=-672.4
\n" ); document.write( "X=-672.4/-.84
\n" ); document.write( "X=800.5 ANSWER FOR THE AMOUNT OF 18% TIN.
\n" ); document.write( "820-800=20 LBS. OF PURE TIN IS USED.
\n" ); document.write( "PROOF.
\n" ); document.write( ".16*800.5+19.5=.18*820
\n" ); document.write( "128.08+19.5=147.6
\n" ); document.write( "147.6~147.6\r
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