document.write( "Question 123407: An alloy of tin is 16% tin. How much tin must be added to make 820 lbs of alloy that is 18% tin? Answer to the nearest tenth. \n" ); document.write( "
Algebra.Com's Answer #90583 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .16X+(820-X)=.18*820 \n" ); document.write( ".16X+820-X=147.6 \n" ); document.write( "-.84X=147.6-820 \n" ); document.write( "-.84=-672.4 \n" ); document.write( "X=-672.4/-.84 \n" ); document.write( "X=800.5 ANSWER FOR THE AMOUNT OF 18% TIN. \n" ); document.write( "820-800=20 LBS. OF PURE TIN IS USED. \n" ); document.write( "PROOF. \n" ); document.write( ".16*800.5+19.5=.18*820 \n" ); document.write( "128.08+19.5=147.6 \n" ); document.write( "147.6~147.6\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |