document.write( "Question 123396: 2a+7=5 \n" ); document.write( "
Algebra.Com's Answer #90564 by praseenakos@yahoo.com(507)\"\" \"About 
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Question:\r
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\n" ); document.write( "\n" ); document.write( "2a+7=5\r
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\n" ); document.write( "\n" ); document.write( "2a + 7 = 5\r
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\n" ); document.write( "\n" ); document.write( "Subtract 7 from both sides....\r
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\n" ); document.write( "\n" ); document.write( "2a + 7 -7 = 5 - 7\r
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\n" ); document.write( "\n" ); document.write( "2a = -2\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"+2a%2F2+++=+-2%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"+a+=+-1\"\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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