document.write( "Question 123158This question is from textbook Algebra And Trigonometry
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document.write( ": A forester mixes gasoline and oil to make 2 gallons of mixture for his two cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and part oil? \n" );
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Algebra.Com's Answer #90562 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A forester mixes gasoline and oil to make 2 gallons of mixture for his two cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and one part oil? \n" ); document.write( ": \n" ); document.write( "The total parts in the original mixture would be: 32 + 1 = 33 parts \n" ); document.write( "The total parts in the new mixture will be: 40 + 1 = 41 parts \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cross multiply \n" ); document.write( "33(x+2) = 41(2) \n" ); document.write( "33x + 66 = 82 \n" ); document.write( "33x = 62 - 66 \n" ); document.write( "33x = 16 \n" ); document.write( "x = 16/33 \n" ); document.write( "x = .48 gal, say, half gallon of gasoline required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( " \n" ); document.write( " |