document.write( "Question 123339: Can you please help me? I have tried working it out but it doesn't check out right.
\n" ); document.write( "(x+7)^3/2=27
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Algebra.Com's Answer #90523 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The way you wrote your problem it could be interpreted in several ways. It could be:
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\n" ); document.write( "\"%28x%2B7%29%5E3%2F2=27\"
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\n" ); document.write( "But I suspect that you meant:
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\n" ); document.write( "\"%28x%2B7%29%5E%283%2F2%29=27\"
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\n" ); document.write( "So I am going to work the second version in which the exponent is \"3%2F2\". If I am not correct
\n" ); document.write( "you will probably need to post your problem again.
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\n" ); document.write( "Starting with:
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\n" ); document.write( "\"%28x%2B7%29%5E%283%2F2%29=27\"
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\n" ); document.write( "You can use the power rule of exponents to rewrite the problem as:
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\n" ); document.write( "\"%28%28x%2B7%29%5E%281%2F2%29%29%5E3+=+27\"
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\n" ); document.write( "Notice that on the right side the 27 is equivalent to \"3%5E3\". Substitute 3 cubed for 27
\n" ); document.write( "and the equation then becomes:
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\n" ); document.write( "\"%28%28x%2B7%29%5E%281%2F2%29%29%5E3+=+3%5E3\"
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\n" ); document.write( "Take the cube root of both sides and the equation reduces to:
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\n" ); document.write( "\"%28x%2B7%29%5E%281%2F2%29+=+3\"
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\n" ); document.write( "Square both sides and the equation is then:
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\n" ); document.write( "\"%28x+%2B+7%29+=+9\"
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\n" ); document.write( "Subtract 7 from both sides and you have:
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\n" ); document.write( "\"x+=+2\"
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\n" ); document.write( "Check ... return to the original problem:
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\n" ); document.write( "\"%28x%2B7%29%5E%283%2F2%29=27\"
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\n" ); document.write( "Substitute 2 for 7 and you have:
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\n" ); document.write( "\"%282%2B7%29%5E%283%2F2%29+=+27\"
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\n" ); document.write( "Combine the 2 + 7 to get 9 and the problem then is:
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\n" ); document.write( "\"%289%29%5E%283%2F2%29+=+27\"
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\n" ); document.write( "You can then take the square root of 9 and cube it or cube 9 and take the square root of that
\n" ); document.write( "with the same result. The square root of 9 is 3 and if you cube 3 you get 27, making the
\n" ); document.write( "equation become 27 = 27. Or you can cube 9 and get 729. Then take the square root of 729
\n" ); document.write( "and get 27 ... again making the equation 27 = 27. Or, since 3/2 = 1.5, you can use a calculator
\n" ); document.write( "and raise 9 to the 1.5 power and you again get 27 ... once more making the equation 27 = 27.
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\n" ); document.write( "In any case x = 2 is a valid solution to the problem.
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\n" ); document.write( "Hope this helps you to understand the problem and how to work it through to a solution.
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