document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123322>Question 123322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr Arnold bought 2 watches and 4 pens for $586. Mr Smith bought 1 watch and 3 pens for $361. Find the cost of the pen. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90502 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let \"w\" be the watch & \"p\" be the pen representations.\r<BR>\n" );
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document.write( "By the given data: \r<BR>\n" );
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document.write( "2w + 4p = 586   ------------------> Arnold \r<BR>\n" );
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document.write( "1w + 3p = 361   ------------------> Smith\r<BR>\n" );
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document.write( "Solving both of the equations simultaneously, we find the value of the pen & the watch. \r<BR>\n" );
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document.write( "2w + 4p = 586\r<BR>\n" );
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document.write( "2w + 6p = 722   multiplied by (2)\r<BR>\n" );
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document.write( "================  Subtracting them we get:<BR>\n" );
document.write( "- 2p = -136 \r<BR>\n" );
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document.write( "==> p = 68 \r<BR>\n" );
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document.write( "So, by back substitution we can find the value of w, watches. \r<BR>\n" );
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document.write( "1w + 3(68) = 361 \r<BR>\n" );
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document.write( "1w = 361 - 204 \r<BR>\n" );
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document.write( "w = 157 \r<BR>\n" );
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document.write( "thus the cost of one pen is $68 and one watch is $157 \r<BR>\n" );
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document.write( "thus the solution.\r<BR>\n" );
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document.write( "regs\r<BR>\n" );
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document.write( " </SPAN>\n" );
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