document.write( "Question 123293This question is from textbook Algebra 1
\n" ); document.write( ": A communications company offers a variety of calling card options. Card A has a 30 cents connection fee and then costs 2 cents per minute. Card B has a 10 cents connection fee and then costs 6 cents per minute. Find the length of the call that would cost the same with both cards.\r
\n" ); document.write( "\n" ); document.write( "It doesn't make sense to me on how to solve it.
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Algebra.Com's Answer #90499 by rajagopalan(174)\"\" \"About 
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Let the lenngth of the call = N minutes
\n" ); document.write( "Cost with Card type \"A\"=30cents+2N cents=30+2N cents
\n" ); document.write( "Cost with Card type \"B\"=10cents+6N cents=10+6N cents
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\n" ); document.write( "Now equate both of the values
\n" ); document.write( "10+6N=30+2N
\n" ); document.write( "6N-2N=30-10
\n" ); document.write( "4N=20
\n" ); document.write( "N=20/4=5 minutes
\n" ); document.write( "For a call lasting 5 minutes the cost via both the cards is one and the same.
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\n" ); document.write( "Verification:\r
\n" ); document.write( "\n" ); document.write( "Type A card cost for 5 min=30cents+2N =30+(2*5)=30+10=40 cents
\n" ); document.write( "Type B card cost for 5 min=10cents+6N =10+(6*5)=10+30=40 cents\r
\n" ); document.write( "\n" ); document.write( "okay
\n" ); document.write( "good day\r
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