document.write( "Question 123287: I have a problem (8th grade) that I can't get started on. \"a group of friends \r
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\n" ); document.write( "\n" ); document.write( "eat at a restaurant and agreed to split the $6.00 bill equally. Two men left without paying and the remaining others were assessed .25 more. How many men in the party originally?\"
\n" ); document.write( "It seems like a linear equation that has 2 variables. How much did each spend and how many men. I can't put it into equation form.
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Algebra.Com's Answer #90470 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
6/X=[6/(X-2)]-.25
\n" ); document.write( "6/X=[6+.25X+.5]/(X-2)
\n" ); document.write( "6(X-2)=X(6-.25X+.5)
\n" ); document.write( "6X-12=6X-.25X^2+.5X
\n" ); document.write( "-.25X^2+.5X+12=0
\n" ); document.write( ".25X^2-.5X-12=0
\n" ); document.write( "(.25X-2)(X+6)=0
\n" ); document.write( ".25X-2=0
\n" ); document.write( ".25X=2
\n" ); document.write( "X=2/.25
\n" ); document.write( "X=8 ANSWER FOR THE NUMBER OF MEN BEFORE 2 LEFT.
\n" ); document.write( "PROOF
\n" ); document.write( "6/8=6/(8-2)-.25
\n" ); document.write( ".75=6/6-.25
\n" ); document.write( ".75=1-.25
\n" ); document.write( ".75=.75
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