document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123289>Question 123289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is twice another number. If the 12 subtracted from the larger number the result is 7 more than the smaller number. Find the numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90465 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be \"x\" \r<BR>\n" );
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document.write( "And twice the number be \"2x\" \r<BR>\n" );
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document.write( "According to the information given, it says \r<BR>\n" );
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document.write( "12 - 2x = 7 + x \r<BR>\n" );
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document.write( "12 - 7 = 3x\r<BR>\n" );
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document.write( "5 = 3x \r<BR>\n" );
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document.write( "x = 5/3 \r<BR>\n" );
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document.write( "Therefore, 2x = 10/3 \r<BR>\n" );
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document.write( "thus, the solution is:\r<BR>\n" );
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document.write( "x = 5/3 and 10/3 \r<BR>\n" );
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document.write( "regs<BR>\n" );
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