document.write( "Question 123285: T=pd/2s+c solve for P= \n" ); document.write( "

Algebra.Com's Answer #90457 by chitra(359) $\"\"$ $\"About$
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The given equation is: \r
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\n" ); document.write( "\n" ); document.write( "T = $\"pd%2F2s+%2B+c\"$ \r
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\n" ); document.write( "\n" ); document.write( "Taking LCM, we get: \r
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\n" ); document.write( "\n" ); document.write( "T = $\"%28pd+%2B+2cs%29%2F2s+\"$ \r
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\n" ); document.write( "\n" ); document.write( "2sT = pd + 2cs \r
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\n" ); document.write( "\n" ); document.write( "2sT - 2cs = pd \r
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\n" ); document.write( "\n" ); document.write( "2s(T - c) = pd \r
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\n" ); document.write( "\n" ); document.write( " $\"2s%28T+-+c%29%2Fd\"$ = p \r
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\n" ); document.write( "\n" ); document.write( "Thus, the solution.\r
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