document.write( "Question 123284: jean is twice as old as bob. the sum of thier ages 3 years ago was 45 years. what are thier ages now?
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Algebra.Com's Answer #90451 by chitra(359)\"\" \"About 
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Let bobs age be \"x\" yrs.\r
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\n" ); document.write( "\n" ); document.write( "So, therefore Jeans age = 2x\r
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\n" ); document.write( "\n" ); document.write( "Given that sum of their ages 3 yrs ago was 45 yrs\r
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\n" ); document.write( "\n" ); document.write( "(x + 2x) - 3 = 45 \r
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\n" ); document.write( "\n" ); document.write( "3x - 3 = 45 \r
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\n" ); document.write( "\n" ); document.write( "3(x - 1) = 45\r
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\n" ); document.write( "\n" ); document.write( "(x - 1) = 45/3 \r
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\n" ); document.write( "\n" ); document.write( "x - 1 = 15 \r
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\n" ); document.write( "\n" ); document.write( "x = 15 + 1\r
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\n" ); document.write( "\n" ); document.write( "x = 16 yrs \r
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\n" ); document.write( "\n" ); document.write( "This is Bobs age \r
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\n" ); document.write( "\n" ); document.write( "So therefore Jeans age is:\r
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\n" ); document.write( "\n" ); document.write( "2(x) = 2(16) \r
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\n" ); document.write( "\n" ); document.write( "= 32 yrs \r
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\n" ); document.write( "\n" ); document.write( "Jeans age is 32 yrs. \r
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\n" ); document.write( "\n" ); document.write( "these are their current ages. \r
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