document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123284>Question 123284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jean is twice as old as bob. the sum of thier ages 3 years ago was 45 years. what are thier ages now?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90444 by </B><A HREF=/tutors/aboutme.mpl?userid=Superownage><B>Superownage(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Superownage><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, this one can be a bit of a problem. Add three years for both of the people, so 51 is the new total. Now jean is 2x (2 times as old as bob) and bob is x, there are three parts of this so 51/3 = bob is 17 and jean is 34 </SPAN>\n" );
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