document.write( "Question 123179: The hypotenuse of a right triangle is 12cm. One side is 2cm longer than the other. FInd the lengths of the two other sides, to the nearest hundreth.\r
\n" ); document.write( "\n" ); document.write( "I keep getting the wrong anwser.
\n" ); document.write( "

Algebra.Com's Answer #90404 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Call the one side, x.
\n" ); document.write( "THe other side is then x+2.
\n" ); document.write( "From the Pythagorean theorem, you know that
\n" ); document.write( "\"x%5E2%2B%28x%2B2%29%5E2=12%5E2\"
\n" ); document.write( "\"x%5E2%2B%28x%5E2%2B4%2Ax%2B4%29=144\"Expand the perfect square.
\n" ); document.write( "\"2x%5E2%2B4x%2B4=144\"Simplify.
\n" ); document.write( "\"2x%5E2%2B4x-140=0\"Bright all terms to one side.
\n" ); document.write( "\"x%5E2%2B2x-70=0\"Divide by 2.
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" Use the quadratic equation.
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A1%2A%28-70%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4%2B280%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28284%29%29%2F%282%29+\"
\n" ); document.write( "\"x%5B1%5D+=+%28-2+%2B+sqrt%28284%29%29%2F%282%29+\"
\n" ); document.write( "\"x%5B2%5D+=+%28-2+-+sqrt%28284%29%29%2F%282%29+\"
\n" ); document.write( "\"x%5B1%5D+=+7.43\"
\n" ); document.write( "\"x%5B2%5D+=+-9.43\"
\n" ); document.write( "Since a negative length does not make sense in this application, use only the positive results.
\n" ); document.write( "x=7.43
\n" ); document.write( "x+2=9.43
\n" ); document.write( "Check the results to verify your answer.
\n" ); document.write( "\"x%5E2%2B%28x%2B2%29%5E2=12%5E2\"
\n" ); document.write( "\"%287.43%29%5E2%2B%289.43%29%5E2=12%5E2\"
\n" ); document.write( "\"55.2049%2B88.9249=144\"
\n" ); document.write( "\"144.1298=144\"
\n" ); document.write( "Look likes that close enough.
\n" ); document.write( "
\n" );