document.write( "Question 122965: The general expression for consecutive multiples of 5 is 5N, 5(N+1), 5(N+2), and so on, where N is some unspecified integer. Find four consecutive multiples of 5 ssuch that 6 times the first is 40 times greater than 2 times the sum of the second and fourth. \n" ); document.write( "
Algebra.Com's Answer #90364 by stanbon(75887)\"\" \"About 
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The general expression for consecutive multiples of 5 is 5N, 5(N+1), 5(N+2), and so on, where N is some unspecified integer. Find four consecutive multiples of 5 ssuch that 6 times the first is 40 greater than 2 times the sum of the second and fourth.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "6*5n = 2[(5(n+1)+5(n+3)]+40
\n" ); document.write( "30n = 2[10n+20]+40
\n" ); document.write( "30n = 20n+80
\n" ); document.write( "10n = -80
\n" ); document.write( "n = -8
\n" ); document.write( "5n=-40
\n" ); document.write( "5(n+1)=-35
\n" ); document.write( "5(n+2)=-30
\n" ); document.write( "5(n+3)=-25
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\n" ); document.write( "Comment: I changed your problem from \"40 times greater than\" to
\n" ); document.write( "40 greater than.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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