document.write( "Question 123086: Mulder leaves Washington at 8:30 a.m. and averages 65 mph. His partner, Scully, leaves at 9:00 a.m., following the same path and averaging 68 mph. At what time will Scully catch up with Mulder?\r
\n" ); document.write( "\n" ); document.write( "The answer is 7:50 p.m. but I need to be shown how to get that answer. Thanks a bunch! \n" ); document.write( "
Algebra.Com's Answer #90338 by rajagopalan(174)\"\" \"About 
You can put this solution on YOUR website!
Mulder leaves Washington at 8:30 a.m.
\n" ); document.write( "speed 65 mph.
\n" ); document.write( "Scully, leaves at 9:00 a.m.,
\n" ); document.write( "sped 68 mph. \r
\n" ); document.write( "\n" ); document.write( "at 900 am
\n" ); document.write( "Mulder has travelled for 30 min (900 am -8:30 am)
\n" ); document.write( "Mulder's speed = 65 mph
\n" ); document.write( "At start distance betwen them=65*(30/60)=32.5 miles\r
\n" ); document.write( "\n" ); document.write( "Appraoch velocity of Scully =speed of Scully - speed of Mulder=68-65=3 mph
\n" ); document.write( "To cover 32.5 miles Scully needs 32.5/3 hours
\n" ); document.write( "=32.5/3=10+(2.5/3)=10+25/30=10+(5/6)=10h+50 minutes\r
\n" ); document.write( "\n" ); document.write( "Scully's start time=9 amm
\n" ); document.write( "add 10 hours and 50 min to 9am=9+10 plus 50 min
\n" ); document.write( "19+50 min
\n" ); document.write( "=7:50 pm
\n" ); document.write( "okay
\n" ); document.write( " \n" ); document.write( "
\n" );