document.write( "Question 123077: Boudreaux rowed his pirogue from his camp on the bayou to his crab traps. Going down the bayou , he caught a falling tide that increased his normal speed by 2 mph but coming back he decreased his speed by 2mph. GOing with the tide, the trip only took 10 min; going against the tide the trip took 30 minutes. How far is it from Boudreaux's camp to his crab traps.
\n" ); document.write( "HINT: With the tide his rate is x+2 mph and against the tide his rate is x-2.
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Algebra.Com's Answer #90337 by rajagopalan(174)\"\" \"About 
You can put this solution on YOUR website!
Onward journey along the stream:
\n" ); document.write( "speed=x+2
\n" ); document.write( "time=10min=10/60=1/6 hour
\n" ); document.write( "distance=speed*time=(1/6)*(x+2)\r
\n" ); document.write( "\n" ); document.write( "return Journey against stream:
\n" ); document.write( "speed=x-2
\n" ); document.write( "time=30min=30/60=1/2 hour
\n" ); document.write( "distance=speed*time=(1/2)*(x+2)\r
\n" ); document.write( "\n" ); document.write( "Equating both distances\r
\n" ); document.write( "\n" ); document.write( "we get
\n" ); document.write( "(1/6)*(x+2)=(1/2)*(x+2)
\n" ); document.write( "multiply throughout by 6,
\n" ); document.write( "x+2=3(x-2)
\n" ); document.write( "x+2=3x-6
\n" ); document.write( "interchange sides
\n" ); document.write( "3x-6=x+2
\n" ); document.write( "3x-x=2+6
\n" ); document.write( "2x=8
\n" ); document.write( "x=4
\n" ); document.write( "***
\n" ); document.write( "Speed DISABLED_event_onward= x+2=6mph
\n" ); document.write( "time=1/6
\n" ); document.write( "Distance=6*1/6=1 mile
\n" ); document.write( "The answer = 1 mile
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\n" ); document.write( "Verification
\n" ); document.write( "Return speed=x-2=4-2=2 mph
\n" ); document.write( "Time=1/2 hour
\n" ); document.write( "Distance=2*(1/2)=1 mile
\n" ); document.write( "okay\r
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