document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122598>Question 122598</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131953648/algebrahomeworkh>blitzer college algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help solve for the following equation:\r<BR>\n" );
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document.write( "A) If y= sqrt x+2, fill in for x=0,1,2,3,4. Round to the nearest three decimal places where necessary.\r<BR>\n" );
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document.write( "Please show work \r<BR>\n" );
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document.write( "B) Explain why no negative values are chosen as values to substitute in for x\r<BR>\n" );
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document.write( "Thank you in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90336 by </B><A HREF=/tutors/aboutme.mpl?userid=gems><B>gems(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gems><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A. for x=0<BR>\n" );
document.write( "y=sqrt x+2<BR>\n" );
document.write( " = sqrt 0+2<BR>\n" );
document.write( "= sqrt 2<BR>\n" );
document.write( "=1.414 approx\r<BR>\n" );
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document.write( "for x = 1<BR>\n" );
document.write( "y = sqrt x+2<BR>\n" );
document.write( "= sqrt 1+2<BR>\n" );
document.write( "=sqrt 3<BR>\n" );
document.write( "= 1.732 approx\r<BR>\n" );
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document.write( "for x=2<BR>\n" );
document.write( "y=sqrt x+2<BR>\n" );
document.write( "= sqrt 2+2<BR>\n" );
document.write( "=sqrt 4<BR>\n" );
document.write( "=2\r<BR>\n" );
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document.write( "for x=3<BR>\n" );
document.write( "y=sqrt x+2<BR>\n" );
document.write( "=sqrt3+2<BR>\n" );
document.write( "=sqrt 5<BR>\n" );
document.write( "= 2.23 approx\r<BR>\n" );
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document.write( "for x=4<BR>\n" );
document.write( "y=sqrt x+2<BR>\n" );
document.write( "=sqrt 4+2<BR>\n" );
document.write( "=sqrt 6<BR>\n" );
document.write( "= 2.449 approx\r<BR>\n" );
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document.write( "B. Negative 1 and negative two can be values for x<BR>\n" );
document.write( "for x= -1<BR>\n" );
document.write( "y=sqrt x+2<BR>\n" );
document.write( "=sqrt -1+2<BR>\n" );
document.write( "=sqrt 1<BR>\n" );
document.write( "=1\r<BR>\n" );
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document.write( "also x=-2<BR>\n" );
document.write( "y=sqrt -2+2<BR>\n" );
document.write( "=sqrt 0<BR>\n" );
document.write( "=0\r<BR>\n" );
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document.write( "Values lower than -2 cannot be used because the radicand becomes negative, and will yield to imaginary number. </SPAN>\n" );
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